Use Graph to Determine Limit: Calculating Limits with Piecewise Functions

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Summary:: Graphs and Limits

Use the graph to determine the limit of the piecewise function as x tends to 1.

Let me see.

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 1.

The limit of f(x) is 1.

Correct?
 

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nycmathguy said:
Summary:: Graphs and Limits

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 1.

The limit of f(x) is 1.

Correct?

Typo ?

##\ ##
 
BvU said:
Typo ?

##\ ##

Yes, big time typo. The limit is clearly 2 not 1. I was rushing through my first reply. Thank you for pointing out my typo. I will repost.
 
I MADE A TYPO AND THUS, DECIDED TO REPOST ORIGINAL THREAD.

Use the graph to determine the limit of the piecewise function as x tends to 1.

Let me see.

lim of (-x + 3) as x-->1 from the left is 2.

lim of (2x) as x-->1 from the right is 2.

I can safely say that the limit of f(x) as x tends to 1 from the left and right simultaneously is 2.

The limit of f(x) is 2.

P. S. Having fun with calculus so far. Hoping the excitement does not run out.
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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