Use spherical cord to compute area of a disk

kougou
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Homework Statement



Use spherical cords to compute area of a disk, that's center at x,y=0, and z=4, having a radius of 3

Homework Equations



I set up a triple ∫∫∫ (r^2* sin(theta)), running from phi =0 to 2pi,
theta=0 to arcsin(3/5), r=5sin(theta) to 5.

The Attempt at a Solution


It doesn't give me a current answer. What's wrong

Am I even on the right track?
 
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kougou said:

Homework Statement



Use spherical cords to compute area of a disk, that's center at x,y=0, and z=4, having a radius of 3

Homework Equations



I set up a triple ∫∫∫ (r^2* sin(theta)), running from phi =0 to 2pi,
theta=0 to arcsin(3/5), r=5sin(theta) to 5.
This is way off. To compute area you need only a single integral or at most a double integral.

Also, you have omitted the differentials on your integral.
kougou said:

The Attempt at a Solution


It doesn't give me a current answer. What's wrong

Am I even on the right track?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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