Use the chain rule to find the derivative

AI Thread Summary
The discussion centers on finding the derivative of the function f(x) = ((x^2+2)^2)/(x+2)^(1/2) using the chain rule. Participants highlight that the problem involves a quotient, suggesting the use of the quotient rule first, which also requires the chain rule. An alternative approach is proposed, recommending rewriting the function to apply the product rule instead. The original poster expresses confusion about the solution provided in the textbook, which is 3x((x^2+2)^(1/2)). The conversation emphasizes the importance of correctly identifying the rules applicable to derivatives in calculus.
Mathysics
Messages
37
Reaction score
0

Homework Statement


f(x) = ((x^2+2)^2)/(x+2)^1/2
Use the chain rule to find the derivative

Homework Equations


None


The Attempt at a Solution


((x^2+2)^2)(x+2)^-1/2

PS: Answer in the book is 3x((x^2+2)^1/2)

I have no idea how they get it there, would like some help, thx!
 
Physics news on Phys.org


Mathysics said:

Homework Statement


f(x) = ((x^2+2)^2)/(x+2)^1/2
Use the chain rule to find the derivative

Homework Equations


None


The Attempt at a Solution


((x^2+2)^2)(x+2)^-1/2

PS: Answer in the book is 3x((x^2+2)^1/2)

I have no idea how they get it there, would like some help, thx!
It looks like you completely missed the fact that this is a quotient (use the quotient rule first). As part of using the quotient rule, you'll need the chain rule.
 


Mark44 said:
It looks like you completely missed the fact that this is a quotient (use the quotient rule first). As part of using the quotient rule, you'll need the chain rule.

ohh thx! I will try it again (reserved)
 


BTW, questions on derivatives really should go in the Calculus & Beyond section, not the Precalc section.
 


Or, since the product rule is (to me anyway) less complicated than the quotient rule, write your function as f(x) = (x^2+2)^2(x+2)^{-1/2} and use the product rule, together with the chain rule.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top