Calculating Force in a Human Cannonball Act: How Is It Done?

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To calculate the average net force exerted on a 72 kg human cannonball shot from an 18m cannon in 0.95 seconds, the acceleration is first determined using kinematics, assuming initial velocity is zero. The calculated acceleration is approximately 40 m/s². Multiplying this acceleration by the mass of the cannonball yields a net force of about 2900 N. The solution is confirmed as correct, indicating a solid understanding of the physics involved. The discussion emphasizes the application of fundamental physics equations in solving real-world problems.
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Homework Statement


During a circus performance a 72 kg human cannonball is shot out of an 18m long cannon. If the human cannonball spends .95 s in the cannon, determine the average net force exerted on him in the barrel in the cannon.


Homework Equations



f=ma
x=v0t + 1/2 at^2 (?)

The Attempt at a Solution



So i solved for acceleration using the kinematics equation, assuming that v0=0
i got approximately 40 m/s^2 and multiplied that by the mass of the man
I got about 2900 N. Is this a good answer? Or did I confuse myself, as usual, when it comes to physics.
 
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Your solution is correct.

ehild
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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