Using a Fourier Cosine Series to evaluate a sum

richyw
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Homework Statement



a) Show that the Fourier Cosine Series of f(x)=x,\quad 0\leq x<L is
x ~ \frac{L}{2}-\frac{4 L}{\pi ^2}\left[\left(\frac{\pi x}{L}\right)+ \frac{\cos\left(\frac{3\pi x}{L}\right)}{3^2}+\frac{\cos\left(\frac{5 \pi x}{L}\right)}{5^2}+\dots\right]

b) use the above series to evaluate the sum1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...

Homework Equations



Fourier Cosine Series General form

The Attempt at a Solution



So I have done part a, but I am lost on how to do part b. I don't understand how to get the even terms? Perhaps I need to differentiate the series, which would pull an n out, making the n's even.

To differentiate term by term a cosine series I need f'(x) to be piecewise continuous. Which I think it is.
 
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Fixed LaTeX:

richyw said:

Homework Statement



a) Show that the Fourier Cosine Series of f(x)=x,\quad 0\leq x<L is
x \sim \frac{L}{2}-\frac{4 L}{\pi ^2}\left[ \cos\left(\frac{\pi x}{L}\right)+ \frac{\cos\left(\frac{3\pi x}{L}\right)}{3^2}+\frac{\cos\left(\frac{5\pi x}{L}\right)}{5^2}+ ...\right]

b) use the above series to evaluate the sum1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...

Homework Equations



Fourier Cosine Series General form

The Attempt at a Solution



So I have done part a, but I am lost on how to do part b. I don't understand how to get the even terms? Perhaps I need to differentiate the series, which would pull an n out, making the n's even.

To differentiate term by term a cosine series I need f'(x) to be piecewise continuous. Which I think it is.
 
micromass said:
Fixed LaTeX:

thanks. I did too. I had to quickly reinstall LaTeXiT from macports :smile:
 
micromass said:
Anyway, what you need to do is choose ##x## (and perhaps ##L##) suitably such that you can extract the series ##\sum \frac{1}{n^2}## out of there.

but my Fourier series only has the odd-n terms?
 
I'll assume the Fourier expansion is correct.

What you need to do is to choose ##x## (and perhaps ##L##) wisely in order to extract an interesting series.

Now, also note the following:

Take

S = 1 + \frac{1}{2^2} + \frac{1}{3^2} + \frac{1}{4^2} + \frac{1}{5^2} + ...

then

S = \left(1 + \frac{1}{3^2} + \frac{1}{5^2} + ... \right) + \left(\frac{1}{2^2} + \frac{1}{4^2} + ...\right)

But

\frac{1}{2^2} + \frac{1}{4^2} + \frac{1}{6^2} + ...= \frac{1}{4}\left(1 + \frac{1}{2^2}+ \frac{1}{3^2} + ...\right)= \frac{S}{4}

So differentiating is unnecessary.
 
ok my initial guess was wrong obviously. becuase it would not make the n's even, it would make them not squared...
 
First think about, what you get, setting x=L. Then you can think further about how to get the given series from this!
 
ok. I don't really have time to show my work, but I ended up with π^2/6. Is this the correct answer?

the trick I didn't get was that part with the s/4
 
richyw said:
ok. I don't really have time to show my work, but I ended up with π^2/6. Is this the correct answer?

the trick I didn't get was that part with the s/4

You have the correct answer!

http://en.wikipedia.org/wiki/Basel_problem
 
  • #10
micromass said:
Fixed LaTeX:

Actually, this is the Fourier series of the even function ##f(x) = |x|, -L \leq x \leq L##, extended to the whole real line as a periodic function of period ##2L##. Basically, the person posing the question needs to specify ##f(x)## outside the desired interval ##[0,L]##. If that is not done correctly the Fourier series won't be pure 'cosine' and/or might not be continuous at ##\pm \, L##, leading to a mis-match between f and the sum of the series at those points.
 
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