Using Gauss' theorem ande exploiting the cylindrical symmetry of the system, show

AI Thread Summary
The discussion focuses on calculating the electric field at the point (L/2, L/100) due to a uniformly charged insulating wire using Gauss' theorem and cylindrical symmetry. The wire has a line charge density lambda and is positioned along the x-axis. The electric field E is derived as E = (100lambda)/(2pi epsilon0 L) by applying Gauss' law, where the area integral simplifies due to symmetry. Participants clarify the correct distance r to use in the calculations, confirming that r equals L/100, as it is the perpendicular distance from the wire to the point of interest. The discussion emphasizes the importance of correctly identifying the geometry in applying Gauss' theorem.
blueyellow

Homework Statement



A wire of length L and negligible transverse dimensions, made of an insulating material, is placed on the x-axis between the origin and the point (L,0). The wire has a uniform line charge density lambda.

using Gauss' theorem and exploiting the cylindrical symmetry of the system, show that the electric field at the point (x,y)=(L/2,L/100) is

E=(100lambda)/(2pi epsilon0 L)

The Attempt at a Solution



integral (S) E.da=E 2 pi r l
Q/(epsilon 0)=(lambda l)/(epsilon0)

2pi r l E=lambda l/epsilon0

E=(1/2 pi r l) (lambda l/epsilon0)
=lambda/(2 pi epsilon0 r)

but I don't know how to proceed from here
 
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Plug in for the given value of r.
 


oh right! so r is just L/100 because it the wire is along the x axis, so I don't have to do L-L/2?
 


blueyellow said:
oh right! so r is just L/100 because it the wire is along the x axis, so I don't have to do L-L/2?
Right. The point where you want to evaluate the field is at a distance of L/100 from the wire, so that's the value of r you need to use.
 
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