Using integration to find limits

waealu
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Homework Statement


The problem asks to integrate dx\(sqrt(abs(x-1))) from 0 to 2.
\int(dx/(sqrt(abs(x-1))))

Homework Equations


I had the limit as b approaches 1 of the integral (from 0 to b) plus the limit as c approaches 1 of the integral (from c to 2).


The Attempt at a Solution


After integrating, I got 2(sqrt(x-1)). Then I plugged in my bounds for the two limit equations and got (0-2)+(2-0)=0. However, I know the answer is 4. What am I missing? I have a feeling that I am forgetting to do something with the absolute value.
 
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waealu said:

Homework Statement


The problem asks to integrate dx\(sqrt(abs(x-1))) from 0 to 2.
\int\frac{}{}dx

Homework Equations


I had the limit as b approaches 1 of the integral (from 0 to b) plus the limit as c approaches 1 of the integral (from c to 2).


The Attempt at a Solution


After integrating, I got 2(sqrt(x-1)). Then I plugged in my bounds for the two limit equations and got (0-2)+(2-0)=0. However, I know the answer is 4. What am I missing? I have a feeling that I am forgetting to do something with the absolute value.

You are forgetting to do something with the absolute value. You can't just integrate pretending it isn't there. |x-1|=x-1 on the interval [1,2] and |x-1|=1-x on the interval [0,1]. Integrate over the two intervals separately and add them.
 
Er Dirk beat me to it.
 
Okay, thanks. I figured it out now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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