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Utter confusion regarding distance covered during acceleration in free fall.

  1. Nov 16, 2012 #1
    Let there be an obj. which is made to fall from a certain height in a gravitaitonal field.

    a= 10 metre per second squared

    Say it falls for 1 second.

    v(final velocity)= 10 metre per second.

    How much distance does it cover in that 1 second?

    distance = speed x time = avg. speed x 1second = 10 m

    This means that 10 m is covered during that 1 second.

    But how could that be when the velocity had not reached 10 metre per second?
  2. jcsd
  3. Nov 16, 2012 #2


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    If acceleration is constant, and if the starting speed is 0 meters per second and the final speed is 10 meters per second, then what is the average speed?
  4. Nov 17, 2012 #3
    thank you. i understood my mistake.
    But now i have another doubt.

    A body falls freely for 10 metres from rest.

    what is the final velocity?

    i found it is sqrt200.
    am i right?

    i found sqrt200.
    am i right?
  5. Nov 17, 2012 #4


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    Correct. You can also write this as 10 x sqrt(2) or ~14.1421. I'm not sure what form of answer your class would prefer.
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