Utter confusion regarding distance covered during acceleration in free fall.

  1. Let there be an obj. which is made to fall from a certain height in a gravitaitonal field.

    a= 10 metre per second squared

    Say it falls for 1 second.

    v(final velocity)= 10 metre per second.

    How much distance does it cover in that 1 second?

    distance = speed x time = avg. speed x 1second = 10 m

    This means that 10 m is covered during that 1 second.

    But how could that be when the velocity had not reached 10 metre per second?
  2. jcsd
  3. rcgldr

    rcgldr 7,651
    Homework Helper

    If acceleration is constant, and if the starting speed is 0 meters per second and the final speed is 10 meters per second, then what is the average speed?
  4. thank you. i understood my mistake.
    But now i have another doubt.

    A body falls freely for 10 metres from rest.

    what is the final velocity?

    i found it is sqrt200.
    am i right?

    i found sqrt200.
    am i right?
  5. rcgldr

    rcgldr 7,651
    Homework Helper

    Correct. You can also write this as 10 x sqrt(2) or ~14.1421. I'm not sure what form of answer your class would prefer.
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