1. The problem statement, all variables and given/known data Benzene, C6H6, has a boiling point of 80 degrees Celsius. The density of benzene vapor in equilibrium with liquid benzene at 50 degrees Celsius is 1.153 g/L. What is the vapor pressure of benzene in mmHg at 50 degrees Celsius? 2. Relevant equations PV=nRt density = m/v 3. The attempt at a solution I thought PV=nRt might cover it.. substituting d=mv into the equation and getting: P = dRt/m Plugging in I get: [(1.153 g/L)(62.364 L Torr/mol K)(323 K)] / (1084.1 g/mol) P = 21.43 Torr = 0.028 mmHg What am I doing wrong? My professor covered what vaporization is, not how to go about getting vaporization pressure. I have a test Wednesday and I don't know how to do any of it!