Variable shift positive clamper

AI Thread Summary
The discussion centers on the output behavior of a variable shift positive clamper circuit when the input voltage is negative. It questions why the output for ωt < π is not equal to Vs + E1, given that Vs is defined as Vm Sinωt. The conversation highlights the role of the capacitor (C) charging to a negative voltage when the input voltage goes negative. It emphasizes the necessity of having a large resistance in series with the capacitor to prevent it from charging to full voltage. The poster expresses uncertainty about the circuit's functionality, indicating a lack of expertise in this area.
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for the given circuit and waveform , i am not getting how output for ωt < π is Vs + E1 ?
given Vs is input and equal to Vm Sinωt
 

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When input voltage goes negative, C will charge to a negative voltage. There should be at least a large resistance resistor in series with C to keep it from charging to full voltage.
This is not my speciality, so there is no guarantee that this circuit will work even with a large resistance resistor in series with C.
 
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