How does air resistance affect terminal velocity for a diver?

AI Thread Summary
Air resistance affects a diver's terminal velocity by increasing with velocity until it nearly equals the diver's weight, resulting in minimal acceleration. The discussion highlights that while air resistance does not increase linearly, it approaches a limit as terminal velocity is approached, theoretically never being fully reached. The concept of drag being proportional to the square of speed is mentioned as a common assumption, although not explicitly stated in the problem. A practical approach using an Excel sheet to model resistance force over time is suggested for better understanding. Ultimately, the diver experiences a gradual increase in air resistance that slows down significantly as they near terminal velocity.
Janiceleong26
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Homework Statement


image.jpg


Homework Equations


F=ma

The Attempt at a Solution


As the diver's velocity increases, then force F due to air resistance would increase, so D is out. And C is out too, as air resistance would be equal to its weight at terminal velocity. The answer is B, but how do we know if the air resistance increases non linearly or linearly?
 
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You are right that it is not easy to show that the resistance does not increase linearly, at least to start with. But is it reasonable that it should suddenly stop increasing at terminal velocity? Indeed, would you expect terminal velocity ever to be actually reached?

Edit: it would be easy to see that it does not start linear if you were told to assume drag is proportional to square of speed, but you are not given that.
 
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not as straightforward as I first thought, try googling "equations for a falling body"
choose an arbitrary Cd value for a free faller (say 0.24)
Set up an excel sheet to create a data table of
time (s) : velocity (m/s) : resistance force (N)
(use elapsed time as the base, say every 1 second)
(resistance force in N = velocity^2 * Cd)
use the time : resistance force results to create a graph
Have fun
 
haruspex said:
You are right that it is not easy to show that the resistance does not increase linearly, at least to start with. But is it reasonable that it should suddenly stop increasing at terminal velocity? Indeed, would you expect terminal velocity ever to be actually reached?

Edit: it would be easy to see that it does not start linear if you were told to assume drag is proportional to square of speed, but you are not given that.
Erm I guess in reality, at terminal velocity, air resistance still increases but in a very very small amount?
I found this explanation in a website:
image.jpg

Thanks for your time :smile:
 
dean barry said:
not as straightforward as I first thought, try googling "equations for a falling body"
choose an arbitrary Cd value for a free faller (say 0.24)
Set up an excel sheet to create a data table of
time (s) : velocity (m/s) : resistance force (N)
(use elapsed time as the base, say every 1 second)
(resistance force in N = velocity^2 * Cd)
use the time : resistance force results to create a graph
Have fun
Ok thx
 
Janiceleong26 said:
Erm I guess in reality, at terminal velocity, air resistance still increases but in a very very small amount?
I found this explanation in a website:
View attachment 91153
Thanks for your time :smile:
Well, no. The point is that the theoretical terminal velocity is a limit, so in theory is never actually reached. Consider a time at which the speed is just 0.01 m/s less than terminal velocity. The air resistance almost equals the weight, so the acceleration is very low, so resistance increases very slowly. On this basis I would reject A because it shows the force increasing linear,y with time, then suddenly levelling out.
 
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haruspex said:
Well, no. The point is that the theoretical terminal velocity is a limit, so in theory is never actually reached. Consider a time at which the speed is just 0.01 m/s less than terminal velocity. The air resistance almost equals the weight, so the acceleration is very low, so resistance increases very slowly. On this basis I would reject A because it shows the force increasing linear,y with time, then suddenly levelling out.
Oh ok thanks
 
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