Vector Addition: Components and Length of Vectors V(1) and V(2)

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SUMMARY

The discussion focuses on the vector addition of two vectors, V(1) and V(2), with components (8.0, -3.7, 0.0) and (3.9, -8.1, -4.4), respectively. The resultant vector's components are calculated as V(x) = 11.9, V(y) = -11.8, and V(z) = -4.4. The magnitude of the resultant vector is determined using the formula √(x² + y² + z²), resulting in a magnitude of approximately 17.3. The calculations and methodology presented are confirmed as correct by other participants in the discussion.

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jena
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Hi,

The question is:

The components of a vector V can be written as (V(x), V(y), V(z)). What are the components and length of a vector which is the sum of the two vectors, V(1) amd V(2). whose components are (8.0. -3.7,0.0) and (3.9,-8.1,-4.4)?

Work

For the components
V(x)= 8.0+3.9=11.9
V(y)=-3.7+-8.1=-11.8
V(z)= 0+-4.4=-4.4


That's all I have figured. I'm a little confused on the set up of this problem. to figure the length would I just use the Pythagorean theorem.

Please help and thank you
 
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The magnitude of a vector is given by

\sqrt{x^2+y^2+z^2}
 
So would the magnitude be

V=((11.9)^2+(-11.8)^2+(-4.4)^2)^(1/2)
V=(300.4)^(1/2)
V=17.3

Is this correct. Also when they refer to components the are referring to these:

V(x)= 8.0+3.9=11.9
V(y)=-3.7+-8.1=-11.8
V(z)= 0+-4.4=-4.4

Thank You
 
yes, that's correct
 

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