Vector analysis homework question

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The discussion revolves around calculating the net force acting on charge q1 in a right-angled triangle configuration of three charges. The values of the charges are q1 = +2.5 x 10^-17 C, q2 = +3.0 x 10^-17 C, and q3 = +3.5 x 10^-17 C, with specified distances between them. The user calculates the forces F1 between q1 and q2, and between q1 and q3, using Coulomb's law. They then attempt to apply the cosine law to find the net force but face questions about the angle used in their calculations. Clarifications are sought regarding the angle and the correctness of the force diagram setup.
chemboy
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3 electrons q1, q2, q3 setup in a right angled triangle

q1
|\
| \
q3-q2

charges are

q1 = +2.5 X 10^-17C
q2 = +3.0 X 10^-17C
q3 = +3.5 X 10^-17C

distances between the charges
q1-q3 = .03 m
q1-q2 = .05 m

setup FBD

\
\ 2F1
\
/
/ 3F1
q1

2F1 = k*q1*q2 / .05^2
= 2.7 X 10^-21N
3F1 = k*q3*q1 / .03^2
= 8.75 X 10^-21N

now I think I use cosine law to figure this out

Fnet = 2F1^2 + 3F1^2 - 2(2F1)(3F1)cos45

is this going the right direction, or did I screw up my FBD
 
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find the magnitude and direction of the force acting on q1
 
chemboy said:
now I think I use cosine law to figure this out

Fnet = 2F1^2 + 3F1^2 - 2(2F1)(3F1)cos45

is this going the right direction, or did I screw up my FBD

Hi chemboy! :smile:

erm … where did 45º come from?

And are you sure that minus should be there? :smile:
 
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