Vector components on Tilted Axis

AI Thread Summary
To find the components N_{x} and N_{y} of vector N in a tilted coordinate system, the correct formulas are N_{x} = -Nsinθ and N_{y} = Ncosθ. The negative sign for N_{x} indicates that the x component points in the negative x direction. This is due to the positive angle being measured from the y-axis towards the negative x-axis. If the angle were measured towards the positive x-axis, it would be negative, and the sign would adjust accordingly. Understanding the orientation of the angle is crucial for determining the correct vector components.
LearninDaMath
Messages
295
Reaction score
0
θ

Homework Statement



Find the components N_{x} and N_{y} of vector N in the tilted cooridinate system.


Homework Equations



cosθ = adg/hyp and sinθ= opp/hyp



The Attempt at a Solution



vectorconfusionc.jpg


The correct answer is supposed to be
N_{x} = -Nsinθ and N_{y} = Ncosθ

The error is on the component vector N_{x}.

How do you find the component vectors and come up with a negative for N_{x}?
 
Last edited:
Physics news on Phys.org
The x component of N is pointing in the -x direction.
That's what the minus sign is telling you.

You have to do this because the positive angle is measured from the y-axis and towards the negative x axis.
If you measured it towards the positive x-axis then the angle shown would be negative, and the sign would take care of itself.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top