Vector Cross Product and Magnitude Calculation

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The discussion revolves around calculating the vector cross product of two vectors, A and B, given in unit vector form. Vector A is 5.00i + 2.00j and Vector B is 3.00i - 1.00j. Participants clarify that while the vectors are expressed in 2D, the cross product yields a k component, suggesting a 3D interpretation. The magnitude of the cross product is calculated using the sine of the angle between the vectors, leading to confusion over the expected results. Ultimately, the original poster resolves their confusion after recalculating the cross product and confirming their understanding.
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2D or 3D vector problem??

Homework Statement


Find the vector product of Vector A cross Vector B(expressed in unit vectors) of the two vectors. What is the magnitude of the vector product?


Homework Equations


Vector A= 5.00i + 2.00j
Vector B= 3.00i - 1.00j



The Attempt at a Solution



I know how to get the dot product of the two, but how do I find the cross product??
 
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This vector problem is 2D. You don't have a k component to represent the third dimension.

The cross product can be evaluated by

U x V = |U||V| * sin(angle between U and V)

|U| this means the "magnitude of U".

Hope that helps.

Thanks
Matt
 


The answer says -17.0k and 17.0. So shouldn't this mean it's a 3D problem? My teacher never taught me this in class and gave us 2 vector problems like this.
 


No this is not a 3D problem. Where could the third dimension come from? The answers are equal and opposite in magnitude, that doesn't mean there is a third dimension.

What is your attempt at the solution? Can you find the magnitudes of the Vector A and Vector B?

Thanks
Matt
 


The magnitude of vector a is 5.38, vector b 3.16. I calculated the angle between the two to be 40.2 degrees. So I took ABsin(40.2) and got my answer is 11.0. The answer in the back says -17.0k, 17.0. I'm confused.. Is the book wrong or me?
 


Nevermind, I solved it.
 


Good then, hope I helped you out.

Thanks
Matt
 
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