Vector Expression of x & y as Function of Time: Unit Vectors i & j

  • Thread starter Thread starter silent bob
  • Start date Start date
  • Tags Tags
    Expression Vector
AI Thread Summary
To express the position as a function of time using unit vectors i and j, the equations x = (12 m/s)t and y = (2.55 m/s)t - (4.9 m/s^2)t^2 can be combined. The position vector can be written as r(t) = x i + y j. Substituting the expressions for x and y, the position vector becomes r(t) = (12 m/s)t i + [(2.55 m/s)t - (4.9 m/s^2)t^2] j. This formulation clearly illustrates the motion in both the x and y directions as functions of time. The final expression captures the vector representation of the position in a two-dimensional space.
silent bob
Messages
7
Reaction score
0
how would i write x= (12 m/s)t , y= (2.55 m/s)t-(4.9 m/s^2)t^2 as a function of time using the unit vectors i and j?
 
Physics news on Phys.org
silent bob said:
how would i write x= (12 m/s)t , y= (2.55 m/s)t-(4.9 m/s^2)t^2 as a function of time using the unit vectors i and j?
Hint: The position is x i + y j
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top