Vector Plane, Calculating Windspeed Question?

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A plane flying south at 480 km/h has a groundspeed of 528 km/h at 15 degrees east of south, prompting a calculation of windspeed and direction. The calculated windspeed is approximately 139.9 km/h, with discussions focusing on the angle measurement. The sine law was used to determine the angle of the wind, yielding an angle of 77.5 degrees east of north. The vector triangle analysis confirms that the greatest angle is opposite the longest side, leading to a final wind direction of 102.5 degrees from the south. The calculations and reasoning demonstrate a clear understanding of vector components in windspeed analysis.
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Homework Statement


A plane initially flies south at a velocity of 480 km/h. Aided by a wind, the groundspeed is 528 kmh at 15 degrees east of south.

Calculate the windspeed and the direction of it






The Attempt at a Solution



I got the magnitude of 139.9 km/h but for the angle I Don't know if the angle is down below the horizontal or above the horizontal.
 
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I don't know which way you're measuring the angle. Pls post your working.
 
Yes, Like this

Untitled2_zps2b530c29.png
 
ok, that's a diagram, but somehow you calculated a speed. Presumably you created an unknown for an angle (which angle?) and wrote down some equations. pls share.
 
haruspex said:
ok, that's a diagram, but somehow you calculated a speed. Presumably you created an unknown for an angle (which angle?) and wrote down some equations. pls share.

Ok I did cos law: Wind = √ (528)^2 + (480)^2 - 2(528)(480)cos15 = 139.9
 
Ok, so pick an angle in the diagram that you want to compute and write down an equation involving it and known distances.
 
haruspex said:
Ok, so pick an angle in the diagram that you want to compute and write down an equation involving it and known distances.

I used the sine law: sintheta/528 = sin15/139.9 = 77.53 degrees... So the picture where the wind goes up?
 
Ok, so you are measuring the wind angle as E of N, and you get 77.5 degrees. Seems reasonable.
 
Well, the longest side of the vector triangle is 528 m, so the greatest angle has to be opposite to it. If one angle is 15° and the other is 77.5°, the third angle is 87.5°: the greatest angle in the triangle, and it is opposite to the side of middle length. So choose 180-77.5 as the angle of the wind.

ehild
 

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