What is the Meaning of Vectorlike Fermion in Particle Physics?

  • Thread starter Thread starter wphysics
  • Start date Start date
  • Tags Tags
    Fermion
wphysics
Messages
27
Reaction score
0
In many papers about hep theory, I can find the concept, vectorlike fermion.

But, I cannot get the exact meaning of vectorlike fermion.

I would like you guys to explain vectorlike fermion.

Thank you.
 
Physics news on Phys.org
It would help if you give some references where they talk about this. Without context it is hard to answer your question.

If I do the googling for you, I come across this paper,

http://deepblue.lib.umich.edu/bitstream/2027.42/28619/1/0000431.pdf

where they seem to explain the term in the introduction very clearly. If you still don't grasp the idea, you should be a bit more specific :)
 
The definition is clear enough. In the Standard Model, the left-handed fermions form isospin doublets, while the right-handed ones form isospin singlets. So the usual mass term, being a product of the two, requires the help of the Higgs field to be gauge invariant. But for these vectorlike fermions, the left- and right-handed components are supposed to transform the same way, making the mass term invariant independently of the Higgs.

The question I have is, why do they refer to them as vector-like.
 
The notion of vector-like originates in the property of the current that couples to the gauge field in question. With a Dirac fermion \Psi, the current \bar{\Psi}\gamma^\mu\Psi is a vector, while \bar{\Psi}\gamma^\mu\gamma^5\Psi is an axial vector. The left-chiral current of the weak interaction is \bar{\Psi}\gamma^\mu(1-\gamma^5)\Psi, hence the name of the "V-A theory."
 
Ok, for a normal fermion, the interaction with the W is V-A. They make no mention of that. But the interaction with the Z, which they do discuss, is a different mixture,
cVγμ - cAγμγ5
where cV = T3 - 2 sin2θW Q and cA = T3.
For the vector-like fermion are they assuming it's an isosinglet?? (So that T3 = 0.) The intro only said the left- and right-handed components were supposed to transform the same way.
 
If by "they," you mean del Aguila et al, the vector-like couplings are listed in Table 1. A vector-like coupling to the Z does not include the \gamma^5 term. There's no connection between c_A and T^3, as the former is identically zero for the new particles. They also allow for the possibility of weak isospin doublet, in which case the W couples to a charged vector current like \bar{N}\gamma^\mu E.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
0
Views
1K
Replies
4
Views
2K
Replies
2
Views
2K
Replies
2
Views
4K
Back
Top