Vector's Cross Product, HELP , Please

AI Thread Summary
The discussion centers on the physical implications of the expression aXb(cosθ) in the context of cross products in vector mathematics. It highlights that the magnitude of this expression represents the projection of vector a onto a unit vector perpendicular to vector b, multiplied by the magnitude of b, with its direction being perpendicular to the plane formed by a and b. This concept is significant in various physical phenomena, such as angular momentum, torque, and the Lorentz force, where relationships depend on components of force or velocity that are perpendicular to radial vectors. The conversation also invites clarification on the angle involved in the expression. Understanding these relationships is crucial for accurately representing vector interactions in physics.
asrith926
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So, the other day, I was learning about Scalars and Vectors and about Dot product and Cross Product. Now, in Cross Product, I was just thinking, when my thought slipped on the following stone:
What is the physical implication of => aXb(cos\vartheta) ?
I mean, how would you represent it on a paper?
 
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asrith926 said:
So, the other day, I was learning about Scalars and Vectors and about Dot product and Cross Product. Now, in Cross Product, I was just thinking, when my thought slipped on the following stone:
What is the physical implication of => aXb(cos\vartheta) ?
I mean, how would you represent it on a paper?
Its magnitude is the projection of a onto the unit vector in the direction perpendicular to the b direction (in the plane made by a and b) multiplied by the magnitude of b. Its direction is perpendicular to the plane made by a and b.

It is defined that way because it is useful. A number of phenomena in physics have relationships that depend on component of a force or velocity perpendicular to a radial vector and proportional to the magnitude of that radius: eg. angular momentum, torque, Lorentz force.

AM
 
What is the physical implication of => aXb(cos)

I'm sorry could you elaborate on this further?

What is the angle you are talking about?
 
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