Vectors Questions Homework - Fundamentals of Physics

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Two physics homework questions involve determining the angle between two equal magnitude vectors A and B, where the magnitude of A+B is significantly greater than A-B. For the first question, the angle must be small, and using the Law of Cosines leads to a calculation that suggests the angle is approximately 1.1458 degrees. The second question generalizes this, indicating that the angle can be found using the arctangent function, specifically aTan(1/n). The discussion highlights the relationship between vector addition and subtraction in a geometric context, confirming the calculations with the help of another participant. The final answers for the angles are confirmed as correct.
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Homework Statement


Ok I did all the chapter 3 questions in Fundamentals of Physics, but I could not get 2 of them.

53. Two vectors A and B have precisely equal magnitudes. For the magnitude of A+B to be 100 times greater that the magnitude of A-B, what must be the angle between them?

54. Two vectors A and B have precisely equal magnitudes. For the magnitude of A+B to be n times greater that the magnitude of A-B, what must be the angle between them?

Homework Equations


Law of Cosines.

The Attempt at a Solution


I am pretty sure the angle has to be small for 53. I know that the magnitude of A is equal to the magnitude of B. Using the Law of Cosines I get cos:smile:=1-mag(A-B)/2A^2. For A+B I get cos:-p=1-50mag(A-B)/A^2. 180-cos:-p=cos:smile:. I don't know where to go after this. I messed around with the equations, but I can't ever get rid of A or B. The second one I have not tried yet, because if I can't the first, then how am I supposed to get the second. THANKS for the help!
 
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Do you know the parallelogram geometric view of addition and subtraction of vectors? Note that in the case that all four sides are equal, you are dealing with a rhombus, for which the diagonals bisect each other in a right angle.
 
Oh got it so, that makes a right triangle with legs 50mag(A-B) and another leg mag(A-B)/2. aTan(1/100)=.5729. Doubling that i get 1.1458 degrees. Right?

For the second one I get aTan(1/n). Right?

Thanks slider142!
 
Yep. Good job!
 
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