Vectors/Trigonometry Notation Problem

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The discussion centers on calculating the magnitude and angle of a vector representing the instantaneous acceleration of a runner, given as <-1.5, 0.5> m/s². The components indicate that the runner's acceleration in the x-direction is -1.5 m/s² and in the y-direction is 0.5 m/s². To find the magnitude, one must apply the Pythagorean theorem, resulting in a magnitude of approximately 1.58 m/s². The angle with respect to the +x axis can be determined using the arctangent function, yielding an angle of approximately 180.0 degrees.

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lando45
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Hey,

I have been set this question:

The instantaneous acceleration of a runner as she rounds the curve on a track is <-1.5 , 0.5> m/s2.What is the magnitude of the acceleration of the runner and what angle does this vector make with respect to the +x axis?

But I don't really understand what the question is asking for, and what the <-1.5 , 0.5> means...any help?

Thanks a lot
 
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I imagine that <-1.5 , 0.5> are the components of her acceleration. i.e. her accln in the x-direction is -1.5 m/s² and in the y-direction, it's 0.5 m/s²


Does that help ?
 

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