Velocity and aceleration relative

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Block A is moving left at 1 m/s with a deceleration of 0.5 m/s², while Block C remains fixed. The discussion highlights that as the pulley moves away from Block C, the length of the rope increases, affecting the motion of Block B. It is established that Block B moves twice as fast as Block A due to the mechanics of the pulley system. The relationship between the distances moved by the pulley and the blocks is crucial for understanding their velocities and accelerations. This analysis provides a clear understanding of the relative motion between the blocks in the system.
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Hello Everybody...

i have some problems to start with this problem someone can help me?
thanks


in the figure, block A moves to the left with a speed of 1m / s, decreasing at a rate of 0.5 m/s2 and block C is fixed. determine the velocity of B relative to A and the acceleration of B relative to A

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Consider this.

Imagine the distance between the pulley and Block C is 1 meter. The distance of the rope is 2 meters since it travels "down and back" from Block C.

So, now let's move the pulley 2 meters away from Block C. Now the rope travels down 2 meters to the pulley and back 2 meters from Block C. This is a total of 4 meters of rope.

So, now let's move the pulley 3 meters away from Block C. Now the rope travels down 3 meters to the pulley and back 3 meters from Block C. This is a total of 6 meters of rope.

This pattern shows that

for whatever distance the pulley moves, its passes though twice as much rope.

Therefore, since the pulley is connected to Block A and the end of the rope is connected to Block B, we can say that Block B moves twice as fast as Block A.
 
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