Velocity as a function of force/impulse/time.

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The discussion focuses on calculating the impulse and final velocity of a 1.5 kg object subjected to a force over time. The impulse is correctly identified as 8 Newton seconds. However, there is confusion regarding the calculation of final velocity, with an initial attempt yielding 3.65 m/s instead of the expected 5.3 m/s. The error is attributed to using the wrong equation for velocity, as the acceleration is not constant in this scenario. The correct approach involves applying the impulse-momentum theorem to find the final velocity accurately.
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Homework Statement



The force shown in the force vs time diagram in Figure P6.11 acts on a 1.5 kg object. Find the impulse of the force, the final velocity of the object if it is initially at rest, and the final velocity if initial velocity is -2.00 m/s.

http://books.google.com/books?id=wD...x_cOMU0&sig=cqAzhugYbnZdpBwdwDdlRM82s1g&hl=en

Homework Equations



V^{2} = V_{0}^{2} + 2a\Deltax

The Attempt at a Solution



I know impulse is just 8 Newton seconds, and i know that's the right answer. But the 2nd question is getting me.

V^{2} = 0 + 2(2/1.5)(5) gives V^{2} = 13.33. so v = 3.65.

But the answer is v = 5.3.

Where did I go wrong?
 
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the7joker7 said:

Homework Equations



V^{2} = V_{0}^{2} + 2a\Deltax
This is when accn is const, which here it's not.

The Attempt at a Solution



I know impulse is just 8 Newton seconds, and i know that's the right answer. But the 2nd question is getting me.

V^{2} = 0 + 2(2/1.5)(5) gives V^{2} = 13.33. so v = 3.65.

But the answer is v = 5.3.

Where did I go wrong?

Use impulse = change in momentum.
 
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