Velocity distribution of evaporating water molecules

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SUMMARY

The velocity distribution of evaporating H2O molecules cannot be described by a Maxwellian distribution due to the nature of molecular interactions during evaporation. The discussion references several academic papers that explore the complexities of this phenomenon, indicating that evaporation does not involve elastic interactions typical of Maxwellian distributions. Key questions arise regarding whether the evaporation process constitutes a two-particle interaction, which directly impacts the distribution of the evaporating molecules.

PREREQUISITES
  • Understanding of molecular dynamics and interactions
  • Familiarity with statistical mechanics concepts
  • Knowledge of the Maxwell-Boltzmann distribution
  • Basic principles of thermodynamics related to phase changes
NEXT STEPS
  • Research the implications of non-elastic interactions in molecular evaporation
  • Study the Maxwell-Boltzmann distribution and its applications
  • Explore the concept of two-particle interactions in thermodynamic processes
  • Investigate alternative models for velocity distributions in evaporating systems
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Researchers in physical chemistry, physicists studying molecular dynamics, and anyone interested in the thermodynamic properties of phase changes in water molecules.

Kazys
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What is the velocity distribution of evaporating H2O molecules? It can not be Maxwellian.
 
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Thank you for the references. They deal with rather specific issues of this general question. I would like to
reframe it in more simple terms. A Maxwellian distribution results when freely moving particles interact
elastically. The question can be posed as follows - is the evaporation of an H2O molecule elastic?
Is it a two particle interaction? If not, can the distribution of evaporating molecules be Maxwellian?
 

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