Velocity Drag force and distance traveled

AI Thread Summary
The discussion focuses on deriving the equation of motion using the relationship between acceleration, velocity, and distance traveled. Participants explore how to express acceleration as a function of velocity and distance, emphasizing the need to clarify which velocity to use in the calculations. The instantaneous velocity is highlighted as crucial for the equation F = ma, leading to the formulation of a differential equation. The conversation also touches on the application of the chain rule to relate acceleration and velocity. Overall, the thread aims to simplify the relationship between these variables for better understanding.
nysnacc
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Homework Statement


Microsoft-Edge-Web-Notes-Mastering61302359[2305843009214067476].jpg


Homework Equations


Sum of force

a = dv/dt
v = integrate a + C

The Attempt at a Solution



I found the equation in terms of final v, initial v... however, on the right hand side, there is another v, and I think it is time dependent, so I am not sure which value should I plug in.
 
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Try using the chain rule to write ##a = \frac{dv}{dt} = \frac{dv}{dx} \frac{dx}{dt}##.
 
Then do we know dv/dx and dx/dt? on the right hand side, will the velocity be initial one? thanks
 
nysnacc said:
Then do we know dv/dx and dx/dt?
Try to express F = ma as a differential equation in terms of just the variables v and x. dv/dx is already expressed in these variables. How can you express dx/dt?

on the right hand side, will the velocity be initial one? thanks
v on the right side of a = F/m is the instantaneous velocity.
 
so dv/dx * dx/dt = -40/m v^2 ??
 
nysnacc said:
so dv/dx * dx/dt = -40/m v^2 ??
Yes. In order to get only the variables v and x to appear in the equation, what can you do with dx/dt?
 
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