Velocity final estimate on frictionless craft

AI Thread Summary
The discussion centers on calculating the estimated final velocity of an R/C hovercraft weighing 6 lbs, powered by a ducted fan with 21.3 ounces of thrust. The user is confused about unit conversions and how to apply the equations of motion, particularly regarding mass and acceleration. They have calculated the thrust force and attempted to find acceleration but are unsure how to proceed without knowledge of calculus. Participants suggest converting all units to the metric system and equating thrust with drag to estimate maximum speed. The conversation emphasizes the importance of understanding the relationship between weight and mass in calculations.
vitologarcia
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Homework Statement


I am trying to calculate the estimated final velocity of a R/C hovercraft i am trying to built. The craft's weight is 6lbs and it is powered by a electric ducted fan that produces 21.3 ounces of thrust. Assuming this craft is actually hovering (no friction with the ground) and has an estimated drag coefficient of .8 (surface area of the front is .33m^2). Time is 6 minutes if needed (half of my battery).


Homework Equations


F=ma
a=f/m
a=(Vf-Vo)/t


The Attempt at a Solution


F=1bf=4.448N
w=f=mg ----- 6lb=m(9.8) ( i am confused with my units)
m=.816
a=F/M=4.448N/.816=5.39m/s^2 ?

I don't know where to go from here, I am just trying to estimate how fast (constant final velocity) i can get this to go on half my battery so that I know how far it will go before I need it to come back.
 
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vitologarcia said:

Homework Statement


I am trying to calculate the estimated final velocity of a R/C hovercraft i am trying to built. The craft's weight is 6lbs and it is powered by a electric ducted fan that produces 21.3 ounces of thrust. Assuming this craft is actually hovering (no friction with the ground) and has an estimated drag coefficient of .8 (surface area of the front is .33m^2). Time is 6 minutes if needed (half of my battery).


Homework Equations


F=ma
a=f/m
a=(Vf-Vo)/t


The Attempt at a Solution


F=1bf=4.448N
w=f=mg ----- 6lb=m(9.8) ( i am confused with my units)
m=.816
a=F/M=4.448N/.816=5.39m/s^2 ?

I don't know where to go from here, I am just trying to estimate how fast (constant final velocity) i can get this to go on half my battery so that I know how far it will go before I need it to come back.

Welcome to the PF. I'm not of any direct help, but the wikipedia page has the general equation for air resistance and other helpful info:

http://en.wikipedia.org/wiki/Air_resistance

It would seem that you would just equate the available driving force of your horiqontal duct with the wind rresistance to find out your max speed, but again, I'm no ME.
 
Thanks
is there anyway you can help me with the acceleration? and my mass? getting it in the right units?
 
vitologarcia said:
Thanks
is there anyway you can help me with the acceleration? and my mass? getting it in the right units?

The sum of all forces F = ma. Convert everything to mks units (meters, kilograms, seconds), and you should be fine. You can calculate your initial acceleration, which will be when there is no wind resistance, and that acceleration will gradually go to zero as you get to speed where the driving and retarding forces match.

If you're familiar with calculus, you can calculate the velocity as a function of time during the ramp up to speed. If not, then you can estimate it in a piecewise fashion (or even use an Excel spreadsheet to get a pretty accurate estimate).
 
actually i am 15 so i don't know calculus but yeah...
8lb=2.72kg

but one is weight and the other is mass, does that matter?
 
vitologarcia said:
actually i am 15 so i don't know calculus but yeah...
8lb=2.72kg

but one is weight and the other is mass, does that matter?

I'm pretty fuzzy on the Imperial unit system, but I believe when you use the conversion 1 = 2.2lb/kg, it's actually pound_mass, as opposed to a pound_force. But don't quote me on that.

Where did you get 8lb = 2.72kg, BTW?
 
sorry that meant to say 6lb=2.72kg
and thanks for all let's see what comes out of this hehe
 
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