Velocity-Friction proportionality.

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The discussion revolves around a physics problem involving a 1000kg boat that experiences a frictional force proportional to its speed after the engine is turned off. The frictional force is defined as Fr = 70 * v, leading to a retarding acceleration of ar = 70/1000 * v. The acceleration is not constant, prompting the use of differential equations rather than standard constant acceleration formulas. By integrating the equation -dv/v = 0.07 dt between the initial speed and half that speed, the time taken for the boat to slow down can be calculated. The solution process is clarified, and participants express gratitude for the insights shared.
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1. A 1000kg boat is traveling across a lake when its engine is shut off. The magnitude of the frictional force between the water and the boat is proportional to the boat's speed (proportionality constant is 70) . Find the time it takes the boat to slow to one half its speed when the engine was shut off.
2.Using Newton's second law: F=ma 3. I'm guessing the acceleration is not constant in this problem. So the constant acceleration equations don't apply. I don't know how to include the time in this problem if i have no equations to solve them in.
Thanx in advance.
 
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At any instant Fr = 70* v.
Or retarding force ar = 70/1000*v Or
-dv/dt = 0.07*v or
-(dv/v) = 0.07*dt.
Take the integration between v to v/2 and find t.
 
Thank you so much ! makes perfect sense now !
 
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