- #1
afaiyaz
Homework Statement
In the figure, a piston P is connected to a cylinder. The piston is connected to a rotating wheel with two shafts AB and BC. The shaft AB is connected on the periphery of the wheel. The wheel is rotating with angular speed ω= 100 rad s-1. At the moment A,C and the center of the wheel is collinear and θ=30° and dθ/dt = 500 rad s-1 , what is the velocity of the piston? (AB = 1.5m, BC = 1m)
Homework Equations
a2 = b2+c2-2abcosθ
Basic Trigonometry
Implicit DIfferentiation
dx/dt = dx/dθ × dθ/dt
The Attempt at a Solution
Since the linking rods are rigid, they must maintain their length throughout.
From the diagram, I assumed a pathway of shaft AB (denoted by y) and used it to find x, which I presumed is the horizontal motion of shaft BC. The rate of change of x with respect to time is, therefore, the velocity of the piston.
My working is as follows:
tan 60 = 1.5/y
∴y=√3/2 m.
Using sine rule,
sin C = y × (sin 120/1)
∴ C = 48.6°
sin (11.4) / x = sin (120) / 1
∴ x=0.228
Using cosine rule,
y2+x2+xy = 1
(2y × dy/dt) + (2x × dx/dt) + (x × dy/dt) + (y × dx/dt) = 0
∴ dx/dt = (- (2y+x) × dy/dt) / (2y+x)
dy/dt = 500 × 1.5 = 750 m/s
Plugging in values of y,x and dy/dt, I get -1111.9≈-1112 m/s.
I feel like this answers very unrealistic as it is more than 3.5 times the speed of sound. Could anyone point out where the mistake is? Could there be a completely different approach to the problem?