Velocity of centre of mass (rolling w/o slipping)

AI Thread Summary
To find the velocity of the center of mass of a glass marble rolling down a 10-degree ramp without slipping, one must consider the conversion of potential energy to kinetic energy. The moment of inertia for a sphere is given as 2/5MR^2, which is essential for calculating rotational motion. The discussion emphasizes the relationship between linear velocity and rotational motion, suggesting that potential energy can be transformed into both translational and rotational kinetic energy. Participants encourage using the problem template for clarity and suggest connecting concepts of energy and motion for a comprehensive understanding. A clear approach to solving the problem involves applying energy conservation principles.
redtrebor
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Find the velocity of the centre of mass of a glass marble which rolls from rest down a
gentle ramp inclined at an angle of 10o
to the horizontal, without slipping, after it has
travelled for a distance of 2.3 m.



Moment of inertia of sphere: 2/5MR^2



Past paper question that I'm really struggling with.
 
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Hi treb, and welcome to PF.
How did you bypass the template ? Folks at PF don't enforce it strictly to pester you! Use it and you'll get answers.
 
Hi, that was as close to the template as i could manage I'm afraid. I really don't know where to start with this question
 
I need a bit more to help you adequately. Ever heard of potential energy ? Can you connect rotation and velocity of center of mass with each other ?
 
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In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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