Velocity of SHM Object at t=0.10s

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The velocity of an object in simple harmonic motion at t=0.10s can be calculated using the formula v=A*√(K/m)*cos(√(K/m)*t). Given the mass (m=36.0g), spring constant (k=400g/s²), amplitude (A=5.0 cm), and time (t=0.10s), the necessary values are provided to solve for velocity. Substituting these values into the formula will yield the object's velocity at the specified time. The discussion emphasizes the importance of correctly applying the formula with the provided parameters. Accurate calculations will lead to the correct answer for the velocity at t=0.10s.
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Homework Statement


At time t, the velocity of v of an object undergoing simple harmonic motion at the end of a spring is given by the formula below. here m is mass of the object (in g), k is a constant depending on the spring (in g/s squared), a is the maximum distance the object moves and t is time (in s).

t=0.10s
m= 36.0g
k= 400g/s][2]
A= 5.0 cm

Homework Equations


v=A*√K/m*cos(√K/m *t)

The Attempt at a Solution

 
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You have a formula for the velocity and the values of all the variables. So what's your attempt at a solution?
 
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