(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two particles each have amass of 5.9e-3 kg.One has a charge of +5.0e-6 C, and theother has a charge of -5.0e-6 C. They are initially held at rest at a distance of0.70 mapart. Both are then released and accelerate toward each other. How fast is each particle moving when the separation between them is one-half its initial value?

2. Relevant equations

[tex]

F = kq1q2/r^2

[/tex]

[tex]

E = F/q

[/tex]

[tex]

V=Ed

[/tex]

[tex]

CV = q

[/tex]

[tex]

Energy = 1/2CV^2

[/tex]

[tex]

KE = 1/2mv^2

[/tex]

3. The attempt at a solution

F = kq1q2/r^2

F = (8.99e9)(5e-6)(5e-6)/.35^2

F = 1.83 N

E = F/q

E = 1.83/5e-6

E = 366,000 N/C

V = Ed

V = (366000)(.35)

V = 128,100 V

q = CV

(5e-6) = (128,100)C

C = 3.90e-11

Energy = 1/2CV^2

Energy = .5(3.9e-11)(128100)^2

Energy = .32 J

KE = 1/2mv^2

.32 = 1/2(5.9e-3)v^2

v = 10.4 m/s

Verification on this would be very greatly appreciated.

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# Homework Help: Velocity of two particles

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