Velocity - time home work check

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SUMMARY

The discussion focuses on a physics homework problem involving a car's motion, where it accelerates from 0 to 30 m/s in 5 seconds, maintains that speed for 15 seconds, and then decelerates to a stop in 10 seconds. The calculated acceleration during the acceleration phase is 6 m/s², while the deceleration phase shows an acceleration of -3 m/s². The total distance traveled is computed as 675 meters, with the constant speed of 30 m/s converted to 108 km/h. The solutions provided are verified and confirmed as correct.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of acceleration and deceleration
  • Ability to convert units (m/s to km/h)
  • Familiarity with calculating distance using time and velocity
NEXT STEPS
  • Study kinematic equations in-depth, focusing on acceleration and distance calculations
  • Learn about unit conversions, specifically between meters per second and kilometers per hour
  • Explore real-world applications of acceleration in automotive physics
  • Practice additional problems involving constant acceleration and deceleration scenarios
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Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics and vehicle acceleration principles.

jacknjersey
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Homework Statement



A car accelerates from 0 to 30m s ^-1 in 5.0 seconds, travels at a constant 30m s^-1 for 15.0 seconds and then brakes to a stop in 10.0 seconds.

1) calculate the acceleration (assumed constant) in each section of the motion.
2) calculate distance travelled
3) what is 30m s^-1 in km/h?

Homework Equations



a= change in velocity / change in time
d(t) = v_0 x t + (a/2)t^2


The Attempt at a Solution



a=(30-0)/5 = 6 m/s
d(t) = 0 x 5 +(6/2_ x 5^2 = 75m

a=(30-30)/15 = 0 m/s^2
d(t) = 30 x 15 + (0/2) x 15^2 = 450m

a=(0-30)/10 = -3m/s^2
d(t) = 30 x 10 + (-3/2) x 10^2 = 150m
 
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Thanks so much! I'm working so slowly trying to get it right. Thanks again, the feedback is a boost!
 

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