Verification of my solution to a problem of Magnetism

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SUMMARY

The discussion centers on the verification of equations related to magnetism, specifically the equations ##\vec{dF} = I \vec{dI} \vec{B}## and ##dT = I \vec{B} \; \vec{dl}##. Participants highlight the ambiguity in the vector products involved and the misrepresentation of ##dT## as a scalar instead of a vector. The need for a free body diagram to accurately represent the forces acting on the segment ##dl## is emphasized, indicating that the tension in the segment should be equated to the magnetic force acting on it.

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  • Knowledge of free body diagrams and their applications
  • Basic principles of electromagnetism
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Swapnil Das
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Your equation for ##\vec{dF} = I \vec{dI} \vec{B}## doesn't make sense as written. How do you interpret ##\vec{dI} \vec{B}##? Is this a product of two vectors? If so, what type of product?

Later you write ##dT = I \vec{B} \; \vec{dl}##. Again the right hand side doesn't indicate the type of product of the two vectors. Also, the left hand side ##dT## is written as a scalar rather than a vector. It appears that you are assuming that the tension in a segment ##dl## is equal to the magnetic force on the segment. Is that correct? You need to draw a free body diagram for the segment ##dl##.
 
Last edited:
TSny said:
Your equation for ##\vec{dF} = I \vec{dI} \vec{B}## doesn't make sense as written. How do you interpret ##\vec{dI} \vec{B}##? Is this a product of two vectors? If so, what type of product?

Later you write ##dT = I \vec{B} \; \vec{dl}##. Again the right hand side doesn't indicate the type of product of the two vectors. Also, the left hand side ##dT## is written as a scalar rather than a vector. It appears that you are assuming that the tension in a segment ##dl## is equal to the magnetic force on the segment. Is that correct? You need to draw a free body diagram for the segment ##dl##.
Thanks a lot, Sir!
 

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