Verify the relation F = m(v^2/r)

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The discussion focuses on verifying the equation F = m(v^2/r) by relating it to Newton's second law, F = ma. Participants express uncertainty about the verification process and highlight the need to understand how centripetal acceleration, a = v^2/r, connects to force. Vector calculus is mentioned as a necessary tool for deriving this relationship, particularly for objects moving along curved paths. A link to an external resource is provided for further guidance on the topic. Overall, the conversation emphasizes the importance of understanding the derivation of centripetal acceleration in relation to force.
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Homework Statement



Use your knowledge of forces to verify the relation F = m(v^2/r)

Homework Equations



None, I think

The Attempt at a Solution



Not sure how to go about verifying this. The only relationship I know of is that a = v^2/r
 
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You also know Newton's 2nd law, don't you?:smile:
 
PhanthomJay said:
You also know Newton's 2nd law, don't you?:smile:

F = ma ; but isn't this wanting me to explain how v^2/r = a ?
 
I don't know. If it is, you have to use vector calculus that derives the centripetal acceleration in terms of a velocity that is changing direction as a particle moves along a curved path of radius r. I suppose you can google it. It was 40 years ago when I last looked at the derivation:bugeye:...not too complicated as I recall.
 
PhanthomJay said:
I don't know. If it is, you have to use vector calculus that derives the centripetal acceleration in terms of a velocity that is changing direction as a particle moves along a curved path of radius r. I suppose you can google it. It was 40 years ago when I last looked at the derivation:bugeye:...not too complicated as I recall.

http://www.practicalphysics.org/go/Guidance_156.html;jsessionid=alZLdQlAHb1?topic_id=3&collection_id=117 is it this?
 
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Thanks..method B was the way I remembered it (and taught it for one year)...time goes by...
 
I found a better source :
 
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