Verifying Stokes' Theorem on F, S in First Octant

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Homework Statement


Verify Stokes' Theorem for F and S
F=(y^2)i+(z^2)j+(x^2)k
S is the first octant portion of x+y+z=1

Homework Equations





The Attempt at a Solution


I know that it should be equal to -1 from Stoke's theorem, but I keep getting 1/4 when I use the normal surface integral way. (I have to do it both ways)

The integral I am using is
\iint x^2 + y^2 + (1-x-y)^2

What am I doing wrong?? :(
 
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I don't think you took the curl of F before you dotted with dS.
 
“The line integral of \v{F} around any closed contour C equals the surface integral (flux) of curl \v{F} over any surface bounded by C

\oint_{C}\v{F}\bullet\v{dl}=\int_{S}\left(Curl\v{F}\right)\bullet\v{dS}

Found these in some of my old undergrad notes...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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