Vertical Deflection Off Free End Of Bar

AI Thread Summary
The discussion focuses on calculating the shear stress and vertical deflection of a steel bar supporting a 152-kg crate. The shear stress was correctly calculated using the formula Stress = F/A, yielding a result of 3,920,000 N/m². However, the method for determining vertical deflection was incorrect; the user initially used an inappropriate formula. The correct formula for cantilever beam deflection under a point load is δ = FL³/3EI, which should be applied for accurate results. Clarification on the correct approach to deflection calculation is emphasized.
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Homework Statement



The drawing shows a 152-kg crate hanging from the end of a steel bar. The length of the bar is 0.09 m, and its cross-sectional area is 3.80x10^-4 m^2. Neglect the weight of the bar itself.

(a) Determine the shear stress on the bar.
(b) Determine the vertical deflection ΔY of the right end of the bar.

Homework Equations


Stress=F/A
Tension=F=ma

Not quite sure what to do with deflection. I found ΔY=(F/A)(L/G) off another posts. Correct to use in this case?

The Attempt at a Solution



(a) This was pretty simple. Just found tension which was (152kg)(9.8). Then divided that by (3.8x10^-4). I got 3920000 N/m^2

(b) This is where I am having trouble. I used the equation off another problem.
This gave me ΔY=(3920000N/m^2)(.09m/(2.0x10^11)).
I found 2.0x10^11 by looking around for Young's Modulus of steel. This gave me an answer of 1.764x10^-6. However, the answer was marked wrong.

Help please!
 
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I assume you have a cantilever type of beam with a point load of 152 kg acting at the free end. In which case for this type of loading, the end deflection is given by

δ= FL3/3EI

Look up cantilever end deflection for definition of the terms.
 
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