Vertical rise of liquid at the back of a linearly accelerating tank....

AI Thread Summary
The discussion centers on the formula for the vertical rise of liquid in a linearly accelerating tank. A participant questions whether the rise should be calculated using the formula Δs = (g + az) Δx / ax. Others point out that this expression is dimensionally inconsistent and cannot hold true when ax equals zero. The conversation emphasizes the importance of proper dimensional analysis in deriving physical equations. Ultimately, the participants clarify that the original formula presented in the notes is correct.
hotjohn
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Homework Statement


why the vertical rise of the surface is given by the formula as shown in the notes ? shouldn't it = Δs =
(g +az ) Δx / ax ?

Homework Equations

The Attempt at a Solution

 

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hotjohn said:
(g +az ) Δx / ax ?
No, it can't be that. Consider ax=0.
How did you arrive at that?
 
Another issue is that your expression is dimensionally inconsistent.
 
gleem said:
Another issue is that your expression is dimensionally inconsistent.
No, I don't think so. az is supposed to be az, an acceleration, etc.
 
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