Very Confused Static Pressure?

AI Thread Summary
To calculate thrust from a propeller, one must first determine the propeller velocity using the formula: prop velocity (pv) = pitch * rpm. This velocity is then used in Bernoulli's equation to find thrust, which involves calculating pressure with the equation pt0 = p0 + 0.5 * r * pv^2. The challenge arises with understanding static pressure (p0), which is crucial for the calculation. In open airflow situations without ducting, static pressure is effectively zero, complicating the thrust calculation. Understanding these concepts is essential for accurate thrust estimation.
Gibbon
Messages
22
Reaction score
0
Hi, I am trying to calculate as best but simply as i can the (approx) thrust from a propeller..

and my research shows i have to calculate:

prop velocity(pv) = pitch * rpm

with pv i can then use Bernoulli's equation to calulate the pressure and multiply it by the propeller surface area to give me thrust.

So ... pt0 = p0 + .5 * r * pv ^2

that equation should give me thrust.. But. p0 is apparently "Static Pressure".. and i cannot for the life of me work out how to calculate static pressure.

Hope you can help, my maths isn't all upto scratch so be kind! :)

Thanks
Andy
 
Physics news on Phys.org
In an open airflow situation (no ducting), there is no static pressure.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top