Very quick question about notation of vector fields

Dvsdvs
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this is a very quick question. my teacher wants me to prove that
((kq)/(sqroot(x^2+y^2+z^2))) (x,y,z) is conservative. by this does it mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))i+((kq)/(sqroot(x^2+y^2+z^2)))j+((kq)/(sqroot(x^2+y^2+z^2)))k

or does it she mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))Xi+((kq)/(sqroot(x^2+y^2+z^2)))Yj+((kq)/(sqroot(x^2+y^2+z^2)))Zk

Basically I am asking if that (x,y,z) is being distrubuted or its just acting as the (i,j,k) itself Thank you very much
Edit oops, forgot the ^3 power in the denominator. But you guys get the point
 
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correct me if I'm wrong but i think it's the second one with the xyz being distributed
 
Dvsdvs said:
this is a very quick question. my teacher wants me to prove that
((kq)/(sqroot(x^2+y^2+z^2))) (x,y,z) is conservative. by this does it mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))i+((kq)/(sqroot(x^2+y^2+z^2)))j+((kq)/(sqroot(x^2+y^2+z^2)))k

or does it she mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))Xi+((kq)/(sqroot(x^2+y^2+z^2)))Yj+((kq)/(sqroot(x^2+y^2+z^2)))Zk

Basically I am asking if that (x,y,z) is being distrubuted or its just acting as the (i,j,k) itself Thank you very much
Edit oops, forgot the ^3 power in the denominator. But you guys get the point

The second one is correct.

It essentially corresponds to the electrostatic field of a point charge at the origin.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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