Vibrating a 75g Bungee Cord: Standing Wave Formation

AI Thread Summary
A 75 g bungee cord with an equilibrium length of 1.20 m is stretched to 1.80 m and vibrated at 20 Hz, creating a standing wave with two antinodes. The user attempts to calculate the spring constant 'k' using the equation w = sqrt(k/m) but is struggling to find the correct value. They initially calculated 'k' as 1184 N/m but suspect it may be incorrect, as they are getting values that are double and half of that. The urgency of the assignment due at 12:00 pm tomorrow adds pressure to resolve the issue. Assistance is sought to clarify the approach to the problem.
strikingleafs01
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Homework Statement


A 75 g bungee cord has an equilibrium length of 1.20 m. The cord is stretched to a length of 1.80 m, then vibrated at 20 Hz. This produces a standing wave with two antinodes.


Homework Equations


I really am not sure how to approach this using an equation, tried to use

w = sqrt (k/m)


The Attempt at a Solution



using the above equation I got a value of

1184 N/m for 'k', which is incorrect
 
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i'm getting now double of that, and half of that value, anyone have any ideas still? this assignment is due 12:00pm tomorrow for us
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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