Visible Light Transitions in Li++ (Z=3)

  • Thread starter Thread starter ChiefKeeper92
  • Start date Start date
  • Tags Tags
    Light Visible light
AI Thread Summary
Visible light transitions in Li++ (Z=3) occur within the 300nm to 700nm wavelength range, with specific transitions identified by their initial and final principal quantum numbers. The formula E=13.6eV*(Z^2)*((1/n)^2-(1/m)^2) is used to calculate energy levels, while λ=1240/E provides the corresponding wavelengths. Users are experiencing issues obtaining different wavelengths from those of hydrogen, suggesting a potential misunderstanding of the calculations, particularly regarding the multiplication of n by Z before squaring. A recommended resource includes a calculator that can assist in determining wavelengths and energies for various transitions. Accurate calculations are essential for identifying visible transitions in hydrogenic lithium ions.
ChiefKeeper92
Messages
5
Reaction score
0
1. Assuming that the wavelengths of visible light lie between about 300nm and 700nm, what transitions in Li++ (hydrogenic lithium ions, Z=3) would be visible. Identify each transition by initial and final principal quantum number n. Also identify those transitions that are also seen in hydrogen (3->2, 4->2, 5->2 in hydrogen)

2. E=13.6eV*(Z^2)*((1/n)^2-(1/m)^2)
λ=1240/E


3. I ran through it but I keep getting the same wavelengths as hydrogen. I don't know what I'm doing wrong. Do I multiply n*Z on the bottom before I square it?
 
Physics news on Phys.org
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top