Voltage: Does Magnitude Affect Electric Field Direction?

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The direction of an electric field is determined by the movement of positive charges, pointing from high voltage to low voltage. While voltage magnitude indicates the strength of the electric field, it does not influence its direction. The common terminology in electronics designates positive voltage as 'high' and negative voltage as 'low,' which can lead to confusion. Ultimately, the electric field direction remains consistent regardless of the voltage's magnitude. Understanding this distinction clarifies misconceptions about voltage and electric field orientation.
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does the magnitude of voltage influence the direction that the electric field points? I am asking because I think I heard that E points from high to low Voltage... is this correct?
 
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The direction of an electric field points the direction in which a + charge will move so it is from + to -
in electronics it is common for + voltage to be called 'high' and - voltage ' low'
I think this is where confusion might come about.
It has got nothing to do with the magnitude of the voltage
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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