Voltage Drop & RE in NPN Transistors

AI Thread Summary
The voltage drop across the emitter in an NPN transistor is not equal to zero; it varies based on the base current. The resistor RE, located after the emitter, plays a crucial role in stabilizing the transistor's operation by influencing the voltage drop across the emitter. When the base current is high, the transistor conducts, resulting in a small voltage across the collector-emitter junction, while the resistors handle most of the supply voltage. Conversely, when the base current is low, the collector-emitter junction stops conducting, leading to a larger voltage drop across it and less voltage across the resistors. Understanding these dynamics is essential for effective transistor circuit design.
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Is the voltage drop across the emitter in an NPN transistor equal to 0?
What is the purpose of RE (found immediately after the emitter?)
 
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I think you're picturing the collector-emitter junction, and one or more resistors in the collector and/or emitter paths, spanning the range between the positive and negative terminals of a power supply. The transistor needs to accommodate two opposite states. If the base current goes high, the transistor conducts, the collector-emitter junction doesn't have much voltage across it, and then the resistors bear most of the power supply voltage. If the base current goes low, the collector-emitter junction stops conducting and takes up a lot more of the power supply voltage, and then the resistors won't don't get the voltage. You're expecting to go back and forth between the situation big X + small Y = constant and the situation small X + big Y= constant.
 
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