Voltage Drops in Series Resistors

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The discussion focuses on calculating the voltage between points P and Q in a circuit with series and parallel resistors. Participants emphasize the importance of correctly identifying which resistors are in series and parallel to simplify the problem. A suggestion is made to visualize the circuit layout to clarify the configuration of the resistors. The voltage across the parallel resistors is confirmed to be 12 volts, but participants note the need to account for voltage drops across all resistors. The conversation highlights the necessity of understanding Ohm's law and the relationships between voltage, current, and resistance in solving the problem.
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Homework Statement


http://imgur.com/bCTKUIs

What is the voltage between P and Q?

Homework Equations

The Attempt at a Solution



Don't know how to begin. I thought maybe I could walk around the circuit to se how the potential changes. Is that a good idea?
 
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You should know Ohms law and how to add resistors in parallel and series configuration.
 
yes I know how to do that. How should a solve this problem?
 
Hi Drizzy:

I think the way the figure is drawn makes it tricky to see what resistances are in series and in parallel. I suggest a layout that shows one resistor with the 12 volts across it, and
the other three resistors as a series of two parts: one with one resistor, and the other with two resistors in parallel.

Good luck.

Regards,
Buzz
 
As you can see resistor 15_ohms and 20ohms share the same nodes, so they are parallel thus can replaced by equivalent resistor.
 
I know that the voltage across the to parallell resistors is 12 aswell. So the current going through it is 12/68,57..

then I can multiply it with 60/7

Is that right?
 
  • #10
Drizzy said:
I know that the voltage across the to parallell resistors is 12 aswell. So the current going through it is 12/68,57..

then I can multiply it with 60/7

Is that right?
No, there is also a voltage drop across the 60 Ω resistor.
 
  • #11
Hi Drizzy:

The diagram linked in your post #7 show two resistances in series. You want to get the voltage drop across one of them. You don't need to calculate any currents. The same current goes through both resistors. You already know the sum of the voltage drops across both resistors.

Hope that helps.

Regards,
Buzz
 
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