What Is the Voltage at Vout With Respect to Ground?

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The discussion focuses on determining the voltage at Vout with respect to ground in a circuit involving resistors and voltage sources. The initial assumption is that Vx is 0V due to grounding, but there is uncertainty about calculating the voltage drop across the resistors. Participants suggest using Kirchhoff's Voltage Law (KVL) to analyze the circuit and find potential differences by summing voltage changes around the loop. They clarify that when connecting voltage sources in series, the total voltage is the sum of the individual sources. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement


I have the following circuit:

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The problem states to give arbitrary values to the resistors, and to find the voltage at Vout with respect to the ground, which I named Vx.


Homework Equations





The Attempt at a Solution


I assume that the voltage at Vx is going to be 0V, due to the ground, but I'm not too sure how to figure out the Voltage at Vout. I know there should be a voltage drop due to the resistor(s), but how to find it is beyond me. I have problems later which I have to find the voltage across a load resistor placed between Vout and Vx, with values given to both resistors in the circuit. Any help on how to figure this one out would be greatly appreciated.
 
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Imagine the circuit is not grounded. What voltage would get across R2?
 
You can obtain the potential difference between any two points of a circuit by 'walking' a KVL path between the points and adding up the changes in potential. You should be able to work out the potential changes across the resistors...
 
So how do I go about doing that with two voltage sources connected into the same loop? I've never seen an example similar to this, so I have nothing to work off of.
 
RIPCLB said:
So how do I go about doing that with two voltage sources connected into the same loop? I've never seen an example similar to this, so I have nothing to work off of.

Write KVL around the loop -- it's the only closed path (circuit) in the diagram, so it's the only path around which a current can flow. Find the voltage drops across the resistors.
 
Are you saying that your course has not covered sources connected in series but you are still given this problem? That would be very strange.

Anyway. When you connect to sources this way, i.e., plus to minus or minus to plus, then the combined voltage at the outer terminals is the sum of the voltages. Which should be fairly intuitive, as you literally stack the sources of top of each other.
 
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