Volume of Gas by Burning Gasoline

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    Gas Gasoline Volume
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Discussion Overview

The discussion revolves around the volume of gas produced from the combustion of gasoline, specifically focusing on the chemical reaction of octane (C8H18) with oxygen (O2). The scope includes theoretical calculations based on molecular weights and stoichiometry.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant inquires about the volume of gas produced from burning a unit of gasoline.
  • Another participant suggests that the calculation can be performed using molecular weights and the molar volume of gas at STP, referencing the combustion reaction of octane.
  • A participant questions the number of water molecules produced in the reaction, suggesting a discrepancy in the stoichiometry.
  • Another participant counters the question by asserting that the original formula correctly accounts for the combustion of 2 moles of octane.

Areas of Agreement / Disagreement

The discussion contains disagreement regarding the stoichiometry of the combustion reaction, particularly the number of water molecules produced. No consensus is reached on this point.

Contextual Notes

Participants have not fully resolved the stoichiometric details of the combustion reaction, and assumptions regarding the reaction conditions are not explicitly stated.

korneld
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What is the volume of gas produced for a unit of gasoline burnt?
 
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It is straight forward to calculate it. Just insert molecular weights in this and use 1 molar volume of a gas is 22.41 liters at STP.

2·C8H18 + 25·O2 => 16·CO2 + 18·H2O

Bob S
 
Thanks for that. Isn't that 9 H2O, though?
 
Can't be, 2 moles of octane were combust in that formula.
 

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