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Volume of solid under graph and above circular region

  1. Nov 1, 2008 #1
    Find the volume of the solid under the graph of z=sqrt(16-x^2-y^2) and above the circular region x^2+y^2<=4 in the xy plane

    I know I must go to polar. So z=sqrt(16-r^2). Does r range from 0-2? I am not sure what theta ranges from (0-2pi)? I set up the integral as int(int r*sqrt(16-r^2), r=0..2), theta=0..2pi) but I get nowhere near any of the answer choices.
     
  2. jcsd
  3. Nov 1, 2008 #2

    tiny-tim

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    Welcome to PF!

    Hi DSnead! Welcome to PF! :smile:
    No, just divide into horizontal slices of thickness dz, and integrate over z. :wink:
     
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