Volume of solids rotating about two axises

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Homework Help Overview

The problem involves finding the volumes of solids of revolution formed by rotating the region bounded by the curve y=2x-x^2 and the line y=0 about the x-axis and y-axis. The original poster expresses confusion regarding the implications of the line y=0 and how it affects the volume calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to visualize the solid formed by the rotation and questions whether their understanding of the cross-sectional area is correct. They also seek clarification on the meaning of the line y=0.
  • Another participant suggests sketching the solids of revolution to aid understanding and discusses the shapes formed when revolving around each axis, mentioning the need to choose an appropriate volume element.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the shapes of the solids and the choice of volume elements, but no consensus has been reached on the original poster's understanding or approach.

Contextual Notes

The original poster notes that the problem may involve two separate calculations for the volumes when revolving around the x-axis and y-axis, indicating a potential complexity in the setup.

PirateFan308
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Homework Statement


Find the volumes of the solids revolution obtained by rotating the region about the x-axis and the y-axis.

y=2x-x^2, y=0



The Attempt at a Solution


I know how to get the volume of a function that is rotating around one axis, but the "y=0" is confusing me. Because y=2x-x^2 is a parabola (with a max at (1,1)), so when I picture it, it looks like a squished donut (with the hole having no area), where a cross sectional area of the donut is shaped like a football with the area being 4/3 (integral of f(x)=2x-x^2 from 0 to 2). The outer radius will be 2 and the inner radius will be 0.

Is this correct, or am I completely off track? Also, what does the y=0 mean? Thanks
 
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PirateFan308 said:

Homework Statement


Find the volumes of the solids revolution obtained by rotating the region about the x-axis and the y-axis.

y=2x-x^2, y=0



The Attempt at a Solution


I know how to get the volume of a function that is rotating around one axis, but the "y=0" is confusing me. Because y=2x-x^2 is a parabola (with a max at (1,1)), so when I picture it, it looks like a squished donut (with the hole having no area), where a cross sectional area of the donut is shaped like a football with the area being 4/3 (integral of f(x)=2x-x^2 from 0 to 2). The outer radius will be 2 and the inner radius will be 0.

Is this correct, or am I completely off track? Also, what does the y=0 mean? Thanks

y=0 is the lower boundary of the region.

As I read it, this is actually two problems: 1) Find the volume when the region is revolved around the x-axis. 2) Find the volume when the region is revolved around the y-axis.
 
Also, you should sketch each of the solids of revolution. When you revolve the region around the x-axis, you get something that looks a little like a football. When you revolve the region around the y-axis, you get something like the upper half of a bagel (what you described as a squished donut).

For the two shapes, you'll need to choose what your typical volume element is - either a disk or a shell. In neither case is the outer radius fixed.
 
Thanks!
 

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