Volume Rate Problem: Find Change When r=6 & 24 Inches

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Homework Statement



The radius r of a sphere is increasing at a rate of 2 inches per minute. Find the rate of chance of the volume when r=6 and r=24 inches.

Homework Equations



V=(4/3)(pi)(r^3)

The Attempt at a Solution



This is what I did, I would appreciate it if someone could tell me if it is correct.

So the volume of a sphere is V=(4/3)(pi)(r^3)

So the first thing I did was derive the equation and got this...

(dv/dt)=(4/3)(3)(pi)(r^2)(dr/dt)

Simplifying it and plugging in 2 for (dr/dt) i got...

(dv/dt)=(8)(pi)(r^2)

So then I just plugged in the r and got 288pi and 4680pi, I have a feeling I've done this terribly wrong though :(
 
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I didn't check your numbers, but your method seems fine to me. However, you might want to get a second opinion before you go and write it in stone.
 
It all looks good to me to. Except for when the radius is 24 I got 4608. Maybe you just had a typo there?
 
yes sorry that was a typo, thanks! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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