Volumetric Expansion: Temperature, Heat & 3 Alpha=Beta

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The discussion centers on explaining the relationship between linear and volumetric thermal expansion coefficients, specifically how 3 alpha equals beta. Participants suggest starting with definitions of the coefficients and considering a cube's volume change in terms of these coefficients. They recommend using a Taylor series expansion to simplify the calculations, specifically the approximation (1+a)^3≈1+3a for small expansions. The conversation emphasizes the importance of understanding the derivation process rather than just receiving answers. Engaging with the outlined steps is encouraged for better comprehension of the concept.
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Hello, Could someone explain to me when referring to temperature and heat, speciffically volume thermal expansion how 3 alpha equals beta? If you could show me in a formula that would be great!
 
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Hi mjongem, welcome to PF. The approximation \beta=3\alpha is something you can prove to yourself.

1. Start with the definitions of linear and volumetric thermal expansion coefficiencts.
2. Considering a cube, write the volume change as a function of unit volume in terms of \alpha and \beta.
3. Assume small expansions compared to the size of the object, and simplify power terms by a Taylor series expansion (e.g., (1+a)^3\approx 1+3a when a is small).
 
I was wondering if you would show me the exact wat to derive my question, I have not taken calculus before, and I just wanted to see how three alpha equals beta
 
We don't just provide solutions here, since that wouldn't help anyone learn. If you show your work in solving a problem, though, you'll usually be able to get help if you get stuck.

If you're interested in solving the problem yourself, try the steps I outlined above. Calculus isn't necessary once you have the approximation (1+\alpha)^3\approx 1+3\alpha.
 
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